counting the no of digits in a given integer

count.py

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+Problem :
+    To count the no of digits given in a number
+My Approach of giving Solution to the solution:
+    step 1 : First define a Funtion named as "countnumbers"
+        step 1.1 : In that, First initalize a variable named as count to Zero (to check how many digits are found in the given number after separation)
+        step 1.2 : Then, Run a while loop untill we separate all the integers from the given number
+            step 1.2.1 : initialize a "temp" variable and store the right most element of the digit
+            step 1.2.2 : Then, increment the count variable by 1 untill the while get ends
+            step 1.2.3 : store the remaining element of the digits after dividing it by 10 in a num and convert to int(num) (type conversio
+Reason for using while loop :
+                    I have used while loop instead of for loop because we could not make sure that when the number get ends                                                                                                          
+ def countnumbers(num):
+     count = 0
+     while (num>0):
+         temp = int(n) % 10
+         count += 1
+         num = int(num) / 10
+         num = int(num)
+
+     return count