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Original file line number Diff line number Diff line change
@@ -0,0 +1,16 @@
from typing import List, Union, Collection, Mapping, Optional
from abc import ABC, abstractmethod

class Solution:
def twoSum(self, nums: List[int], target: int) -> List[int]:

answer = dict()

for k, v in enumerate(nums):

if v in answer:
return [answer[v], k]
else:
answer[target - v] = k

return []
Original file line number Diff line number Diff line change
@@ -0,0 +1,23 @@
from typing import List, Union, Collection, Mapping, Optional
from abc import ABC, abstractmethod
import re

class Solution:
def isPalindrome(self, s: str) -> bool:

# To lowercase
s = s.lower()

# Remove non-alphanumeric characters
s = re.sub(pattern=r'[^a-zA-Z0-9]', repl='', string=s)

# Determine if s is palindrome or not

len_s = len(s)

for i in range(len_s//2):

if s[i] != s[len_s - 1 - i]:
return False

return True
Original file line number Diff line number Diff line change
@@ -0,0 +1,17 @@
from typing import List, Union, Collection, Mapping, Optional
from abc import ABC, abstractmethod

class Solution:
def minimumSwaps(self, nums: List[int]) -> int:

min_num = min(nums)
max_num = max(nums)

id_min = nums.index(min_num)

new_nums = [min_num] + nums[:id_min] + nums[id_min + 1:]

id_max = new_nums[::-1].index(max_num)

return id_min + id_max

Original file line number Diff line number Diff line change
@@ -0,0 +1,40 @@
from typing import List, Union, Collection, Mapping, Optional
from abc import ABC, abstractmethod
from collections import Counter

class Solution:
def minimumKeypresses(self, s: str) -> int:
"""
Greedy approach: Assign most frequent characters to 1-press slots

Example: s = "apple"
Frequency: {'p': 2, 'a': 1, 'l': 1, 'e': 1}

Assignment:
- 'p' (freq=2) → position 0 → 1 press → total: 2 * 1 = 2
- 'a' (freq=1) → position 1 → 1 press → total: 1 * 1 = 1
- 'l' (freq=1) → position 2 → 1 press → total: 1 * 1 = 1
- 'e' (freq=1) → position 3 → 1 press → total: 1 * 1 = 1

Total: 2 + 1 + 1 + 1 = 5
"""

# Count character frequencies
freq = Counter(s)
print(freq)

# Sort by frequency (descending) - greedy choice
counts = sorted(freq.values(), reverse=True)
print(counts)

total_presses = 0

# Calculate presses based on position
for position, frequency in enumerate(counts):
# Positions 0-8: 1 press (9 slots)
# Positions 9-17: 2 presses (9 slots)
# Positions 18-26: 3 presses (9 slots)
presses_per_char = (position // 9) + 1
total_presses += presses_per_char * frequency

return total_presses
20 changes: 20 additions & 0 deletions src/my_project/interviews/top_150_questions_round_21/plus_one.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,20 @@
from typing import List, Union, Collection, Mapping, Optional
from abc import ABC, abstractmethod

class Solution:
def plusOne(self, digits: List[int]) -> List[int]:

len_digits = len(digits)

for i in range(len_digits - 1, -1, -1):

if digits[i] != 9:
digits[i] += 1
break
else:
digits[i] = 0

if digits[0] == 0:
return [1] + digits
else:
return digits
19 changes: 19 additions & 0 deletions tests/test_150_questions_round_21/test_plus_one_round_21.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,19 @@
import unittest
from src.my_project.interviews.top_150_questions_round_21\
.plus_one import Solution

class PlusOneTestCase(unittest.TestCase):

def test_leading_one(self):
solution = Solution()
output = solution.plusOne(digits=[9])
target = [1, 0]
for k, v in enumerate(target):
self.assertEqual(v, output[k])

def test_no_leading_one(self):
solution = Solution()
output = solution.plusOne(digits=[1, 2])
target = [1, 3]
for k, v in enumerate(target):
self.assertEqual(v, output[k])