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Why use scipy.io.wave rather than stdlib wave? #3

@Russell-Jones

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@Russell-Jones

Rather than
self.wav = scipy.io.wavfile.read(self.wavPath)
why not
self.wav = wave.open(self.wavPath, 'rb').readframes()
?

It's available in Python 2.6+ https://docs.python.org/2.6/library/wave.html
Is it to avoid type conversion complexities in 2.x?

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