feat: add sql solution to lc problem: No.601 (#4807)

Author: hhnguyen-20

solution/0600-0699/0601.Human Traffic of Stadium/README.md

@@ -105,4 +105,38 @@ ORDER BY 1;
 
 <!-- solution:end -->
 
+<!-- solution:start -->
+
+### 方法二
+
+<!-- tabs:start -->
+
+#### MySQL
+
+```sql
+# Write your MySQL query statement below
+WITH
+    Consecutive AS (
+        SELECT
+            *,
+            id - ROW_NUMBER() OVER () AS id_diff
+        FROM Stadium
+        WHERE people >= 100
+    )
+SELECT id, visit_date, people
+FROM Consecutive
+WHERE
+    id_diff IN (
+        SELECT id_diff
+        FROM Consecutive
+        GROUP BY id_diff
+        HAVING COUNT(*) > 2
+    )
+ORDER BY visit_date;
+```
+
+<!-- tabs:end -->
+
+<!-- solution:end -->
+
 <!-- problem:end -->

solution/0600-0699/0601.Human Traffic of Stadium/README_EN.md

@@ -104,4 +104,38 @@ ORDER BY 1;
 
 <!-- solution:end -->
 
+<!-- solution:start -->
+
+### Solution 2
+
+<!-- tabs:start -->
+
+#### MySQL
+
+```sql
+# Write your MySQL query statement below
+WITH
+    Consecutive AS (
+        SELECT
+            *,
+            id - ROW_NUMBER() OVER () AS id_diff
+        FROM Stadium
+        WHERE people >= 100
+    )
+SELECT id, visit_date, people
+FROM Consecutive
+WHERE
+    id_diff IN (
+        SELECT id_diff
+        FROM Consecutive
+        GROUP BY id_diff
+        HAVING COUNT(*) > 2
+    )
+ORDER BY visit_date;
+```
+
+<!-- tabs:end -->
+
+<!-- solution:end -->
+
 <!-- problem:end -->

solution/0600-0699/0601.Human Traffic of Stadium/Solution2.sql

@@ -0,0 +1,19 @@
+# Write your MySQL query statement below
+WITH
+    Consecutive AS (
+        SELECT
+            *,
+            id - ROW_NUMBER() OVER () AS id_diff
+        FROM Stadium
+        WHERE people >= 100
+    )
+SELECT id, visit_date, people
+FROM Consecutive
+WHERE
+    id_diff IN (
+        SELECT id_diff
+        FROM Consecutive
+        GROUP BY id_diff
+        HAVING COUNT(*) > 2
+    )
+ORDER BY visit_date;