Java：APIJSONBoot 和 APIJSONFinal 登录接口兼容 MySQL 5.6 及以下等不支持 json 类型的数据库

Author: TommyLemon

APIJSON-Java-Server/APIJSONBoot/src/main/java/apijson/boot/DemoController.java

@@ -596,7 +596,12 @@ public JSONObject login(@RequestBody String request, HttpSession session) {
 
 		response = new JSONResponse(
 				new DemoParser(GETS, false).parseResponse(
-						new JSONRequest(new User(userId)).setFormat(true)
+						new JSONRequest(  // 兼容 MySQL 5.6 及以下等不支持 json 类型的数据库
+								USER_,  // User 里在 setContactIdList(List<Long>) 后加 setContactIdList(String) 没用
+								new apijson.JSONObject(  // fastjson 查到一个就不继续了，所以只能加到前面或者只有这一个，但这样反过来不兼容 5.7+
+										new User(userId)  // 所以就用 @json 来强制转为 JSONArray，保证有效
+										).setJson("contactIdList,pictureList")
+								).setFormat(true)
 						)
 				);
 		User user = response.getObject(User.class);

APIJSON-Java-Server/APIJSONBoot/src/main/java/apijson/demo/model/User.java

@@ -19,7 +19,6 @@
 
 import java.util.List;
 
-import apijson.JSON;
 import apijson.MethodAccess;
 import apijson.framework.BaseModel;
 import apijson.orm.Visitor;
@@ -63,31 +62,30 @@ public User setSex(Integer sex) {
 		this.sex = sex;
 		return this;
 	}
+	
 	public String getHead() {
 		return head;
 	}
 	public User setHead(String head) {
 		this.head = head;
 		return this;
 	}
+	
 	public String getName() {
 		return name;
 	}
 	public User setName(String name) {
 		this.name = name;
 		return this;
 	}
+	
 	public List<String> getPictureList() {
 		return pictureList;
 	}
 	public User setPictureList(List<String> pictureList) {
 		this.pictureList = pictureList;
 		return this;
 	}
-	public User setPictureList(String pictureList) {  // 兼容 MySQL 5.6 及以下等不支持 json 类型的数据库
-		this.pictureList = JSON.parseArray(pictureList, String.class);
-		return this;
-	}
 
 	public String getTag() {
 		return tag;
@@ -104,10 +102,5 @@ public User setContactIdList(List<Long> contactIdList) {
 		this.contactIdList = contactIdList;
 		return this;
 	}
-	public User setContactIdList(String contactIdList) {  // 兼容 MySQL 5.6 及以下等不支持 json 类型的数据库
-		this.contactIdList = JSON.parseArray(contactIdList, Long.class);
-		return this;
-	}
-
 
 }

APIJSON-Java-Server/APIJSONFinal/src/main/java/apijson/demo/model/User.java

@@ -19,7 +19,6 @@
 
 import java.util.List;
 
-import apijson.JSON;
 import apijson.MethodAccess;
 import apijson.framework.BaseModel;
 import apijson.orm.Visitor;
@@ -63,31 +62,30 @@ public User setSex(Integer sex) {
 		this.sex = sex;
 		return this;
 	}
+	
 	public String getHead() {
 		return head;
 	}
 	public User setHead(String head) {
 		this.head = head;
 		return this;
 	}
+	
 	public String getName() {
 		return name;
 	}
 	public User setName(String name) {
 		this.name = name;
 		return this;
 	}
+	
 	public List<String> getPictureList() {
 		return pictureList;
 	}
 	public User setPictureList(List<String> pictureList) {
 		this.pictureList = pictureList;
 		return this;
 	}
-	public User setPictureList(String pictureList) {  // 兼容 MySQL 5.6 及以下等不支持 json 类型的数据库
-		this.pictureList = JSON.parseArray(pictureList, String.class);
-		return this;
-	}
 
 	public String getTag() {
 		return tag;
@@ -104,10 +102,5 @@ public User setContactIdList(List<Long> contactIdList) {
 		this.contactIdList = contactIdList;
 		return this;
 	}
-	public User setContactIdList(String contactIdList) {  // 兼容 MySQL 5.6 及以下等不支持 json 类型的数据库
-		this.contactIdList = JSON.parseArray(contactIdList, Long.class);
-		return this;
-	}
-
 
 }

APIJSON-Java-Server/APIJSONFinal/src/main/java/apijson/jfinal/DemoController.java

@@ -549,7 +549,12 @@ public void login() {
 
 		response = new JSONResponse(
 				new DemoParser(GETS, false).parseResponse(
-						new JSONRequest(new User(userId)).setFormat(true)
+						new JSONRequest(  // 兼容 MySQL 5.6 及以下等不支持 json 类型的数据库
+								USER_,  // User 里在 setContactIdList(List<Long>) 后加 setContactIdList(String) 没用
+								new apijson.JSONObject(  // fastjson 查到一个就不继续了，所以只能加到前面或者只有这一个，但这样反过来不兼容 5.7+
+										new User(userId)  // 所以就用 @json 来强制转为 JSONArray，保证有效
+										).setJson("contactIdList,pictureList")
+								).setFormat(true)
 						)
 				);
 		User user = response.getObject(User.class);